in PYTHON i have one list and i want to make from it a multiple lists, for every item i want him to create a list with the other items
my initial list :
cities = ['Chevalley', 'A.Gharmoul 1', 'El Madania']then i want the output to be :
[
['Chevalley', 'A.Gharmoul 1'],
['Chevalley','El Madania'],
['A.Gharmoul 1', 'El Madania']
]The below code will help you to create the resultant list you are looking for:
items = ['Chevalley', 'A.Gharmoul 1', 'El Madania']
res = [[items[i],items[j]] for i in range(len(items)) for j in range(i+1, len(items))]
print(res)
result_list = []
for i in ['Chevalley', 'A.Gharmoul 1', 'El Madania']:
for j in ['Chevalley', 'A.Gharmoul 1', 'El Madania']:
if i != j:
result_list.append([i, j])
It should iterate over every possible pairing while ignoring pairing element with itself.
while this isn't the same it is pretty close to what you are looking for.
import itertools
a = ['Chevalley', 'A.Gharmoul 1', 'El Madania']
result = list(itertools.combinations(a,2)) # number is the amount of items you want in the resultant tuple
result will have tuples of length 2 in a list.
Below should do it:
l = ['Chevalley', 'A.Gharmoul 1', 'El Madania']
n = [[l[i], l[j]] for i in range(0, len(l) - 1, 1) for j in range(i + 1, len(l), 1)]
n will equate to:
[['Chevalley', 'A.Gharmoul 1'],
['Chevalley', 'El Madania'],
['A.Gharmoul 1', 'El Madania']]
nested for loops does your work
list1 =['Chevalley', 'A.Gharmoul 1', 'El Madania']
output =[]
for i in range(len(list1)):
for j in range(i+1,len(list1)):
output.append([list1[i],list1[j]])
print(output)#[['Chevalley', 'A.Gharmoul 1'],['Chevalley','El Madania',['A.Gharmoul 1', 'El Madania']]
You can use itertools and convert the output tuples into lists:
import itertools
new = [ list(el) for el in itertools.combinations(['Chevalley', 'A.Gharmoul 1', 'El Madania'], 2) ]
