How to run Curl Command in Python

Question

I want to run Following Curl Command in Python and I was trying the requests command of python but I am not getting the proper results.

curl -v ftp://ftp.abc.com/File.txt --socks5-hostname socks.abc.com:PORT --user username:password -O

what do you try to do and why you can not do it in python?

balderman
– balderman

2020-10-27 12:43:01 +00:00
Commented Oct 27, 2020 at 12:43 — balderman
– balderman, Commented Oct 27, 2020 at 12:43

max wiklund · Accepted Answer · 2020-10-27 13:47:58Z

1

You can use subprocess.

import subprocess
result = subprocess.run(["curl", "-v", "ftp://ftp.abc.com/File.txt --socks5-hostname socks.abc.com:PORT --user username:password -O"], capture_output=True)
print(result.stdout)

I'm not into web development but this looks like something the requests module should be able to handle.

r = requests.get('https://api.github.com/user', auth=('user', 'pass'))
r.status_code

https://requests.readthedocs.io/en/master/

answered Oct 27, 2020 at 13:47

max wiklund

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