2-D array and pointer to 2-D array

Question

int main()
{
int arr[][3]={{1,2},{3,4},{4,5}};
int (*p)[3];
p=arr;
cout<<sizeof(p)<<" "<<sizeof(*p);
return 0;
}

Above is my code,the output of this code is 4 12.So my doubt is what do the complier interpret p and *p as ? what they are actually pointing to?

Rweinz · Accepted Answer · 2020-10-29 16:45:05Z

1

P is a pointer, you probably have a 32-bit system, therefore sizeof(p) returns 4. Then you defined p as a pointer to an array of 3 ints, the sizeof int is 4, so the sizeof what it's pointing to, sizeof(*p) is 12.

answered Oct 29, 2020 at 16:45

Rweinz

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