Regular expression split in python

Question

Could you please let me know how does we split a string with multiple delimiters in python and one of the delimited is a text

for example, we have a string 'this is my worksplace.Work restricted.this is a sample text.this is text 2.Work restricted'

I want a split using dot first and then with 'Work restricted'

I did a regular expression using dot and able to get the list, sample below

textforsplit='this is my worksplace.Work restricted.this is a sample text.this is text 2.Work restricted'
testArray=re.split('[.]',textforsplit)

this is working with dot and I am able to get the list as

['this is my worksplace','Work restricted','this is a sample text','this is text2', 'Work restricted']

But I want to filter the results again and need to get a list excluding the 'Work restricted' text, that is the final list should be

['this is my worksplace','this is a sample text, 'this is text 2']

is there anyway I can achieve this using modifications in the regular expression conditions in python

thank you

Barmar · Accepted Answer · 2020-10-31 07:35:28Z

1

There's no need to use a regular expression for this, since the delimiter is a fixed string. Just use the regular str.split() method. Then you can remove Work restricted using a list comprehension.

textforsplit='this is my worksplace.Work restricted.this is a sample text'
testArray=textforsplit.split('.')
testArray = [x for x in testArray if x != 'Work restricted']

edited Oct 31, 2020 at 7:35

answered Oct 31, 2020 at 7:23

Barmar

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5 Comments

user1293071 Over a year ago

thank you for your response, I updated the question to avoid confusion, first we have to split with dot and then with 'Word restricted'. Could you please help

user1293071 Over a year ago

thanks much, this works, I will test all the conditions and update

user1293071 Over a year ago

Can we add multiple conditions in the if statement, one scenario is the string can be like 'this is a simple text.Work restricted.' there can be a dot at the end and the split will create a empty list element ''. here, ['this is a simple text','Work restricted','']. So, I need to remove the empty elements ''. So, in the if condition I can check for the != 'Work restricted or '', correct?

Barmar Over a year ago

if x != 'Work restricted' and x != '' and ...

Barmar Over a year ago

or if x not in {'Work restricted', '', ...}

avarice · Accepted Answer · 2020-10-31 07:03:50Z

1

You can filter them with a list comprehension:

testArray = [x for x in testArray if x != 'Work restricted']

answered Oct 31, 2020 at 7:03

avarice

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1 Comment

user1293071 Over a year ago

thank you for your response, I updated the question to avoid confusion, first we have to split with dot and then with 'Word restricted'. Could you please help

anubhava · Accepted Answer · 2020-10-31 07:48:12Z

1

Here is a pure regex solution using findall:

>>> textforsplit='this is my worksplace.Work restricted.this is a sample text.this is text 2.Work restricted'
>>> print ( re.findall(r'(?:^|(?<=\.))(?!Work restricted)[^.]+', textforsplit) )
['this is my worksplace', 'this is a sample text', 'this is text 2']

RegEx Demo

RegEx Details:

(?:^|(?<=\.)): If we are start or previous character is a dot
(?!Work restricted): Negative lookahead to assert that we don't have Work restricted ahead of us
[^.]+: Match 1+ of any character that is not DOT

answered Oct 31, 2020 at 7:48

anubhava

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