JUnit 3 - Array contains a given element

Question

I am trying to assert that a given array contains at least one instance of a given element. Is there an assert method that already does this? If so which one?

I am using Java6 and JUnit3.

Mark Wiemer · Accepted Answer · 2018-07-10 05:57:06Z

42

You can cast the array to a list:

assertTrue(Arrays.asList(yourArray).contains(yourElement));

edited Jul 10, 2018 at 5:57

Mark Wiemer

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answered Jun 24, 2011 at 15:31

Kevin Bowersox

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bheussler · Accepted Answer · 2016-11-30 23:10:34Z

16

assertThat(Arrays.asList(yourArray), hasItem(yourElement));

This will give you fine-grained information in the event of a test failure. It will print out your element and the collection it's looking in.

answered Nov 30, 2016 at 23:10

bheussler

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3 Comments

Sungam Over a year ago

This is the best answer. is 'hasItem' new?

bheussler Over a year ago

@Sungam hasItem() is a part of Java Hamcrest, which was last updated in 2012.

Michi-2142 Over a year ago

hasItem() is deprecated

highlycaffeinated · Accepted Answer · 2011-06-24 15:29:09Z

14

Not a built-in assert, no. You'd need to use assertTrue() and check the array yourself using something like Arrays.binarySearch(), ArrayUtils.contains(), or your own method.

answered Jun 24, 2011 at 15:29

highlycaffeinated

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2 Comments

hvgotcodes Over a year ago

the thing I would add is the user might want to build their own TestUtil that has a method testArrayContains(ary, object)

Tiago Veloso Over a year ago

I went with the ArrayUtils approach, It seems my Project is including Apache Commons. I was about to create my own method, but I might as well use that one.

yoAlex5 · Accepted Answer · 2019-08-06 14:40:36Z

1

You can try containsInAnyOrder

assertThat(actual, containsInAnyOrder(expected));

answered Aug 6, 2019 at 14:40

yoAlex5

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