Suppose I have a string str='4 for 9'.The numbers in string might differ i want to obtain the left and right text of word for that is 4,9 I have tried it with split function .Is there any regular expression i can use to obtain this?
str='4 for 9'
for_exp=str.split('for')
With regex,
In [1]: import re
In [2]: regex = re.compile('([\s \S]*) for ([\s \S]*)')
In [3]: str='4 for 9'
In [4]: regex.match(str).groups()
Out[1]: ('4', '9')
In [5]: regex.match("44 for 54").groups()
Out[2]: ('44', '54')
In [6]: regex.match("44 advg for 54 2243").groups()
Out[3]: ('44 advg', '54 2243')
If you put a pattern in (), the regex will consider it as a group. So after a match is found, you can look at the various groups in the match using the groups() method.
It returns a tuple of size equal to the number of groups you defined in your regex.
I am matchin on \s \S on either side of for. This will match anything (all non space and space characters).
If you want onyl numbers, limit the regex to \d+ instead.
A string in Python is actually also a list of characters, so you can do this if there is only 1 digit
a = str[0]
b = str[-1]
if you wanna use regex, for 1 or more digits
number = re.search('(\d+)\sfor\s(\d+)', str)
The first element is the matched result, while number[1] and number[2] hold the start and end digit.
