I have text file with symbols (sss7775aaaa 4444a 555dussns6 7djshs8 4sssss sssss oooo) and I need to find only whose words, which has numbers in.
I think program somehow should put all symbols seperated by spaces into array and then chech every single array element. But I'm not sure how to do it.
Thanks.
You can use the following code to do what you have in mind:
# This list will store the words that contain numbers.
words_with_numbers = []
f = open('file.txt', 'r')
for line in f:
line = line.strip()
words = line.split(' ')
for w in words:
if any(c.isdigit() for c in w):
words_with_numbers.append(w)
f.close()
Ref: https://docs.python.org/2/library/stdtypes.html#str.isdigit
break after .append(w) should reduce the number of characters checked.If you have a string variable you can use the str.split() function to split the data by a separator, a space by default. This will return a list of strings.
You can then iterate each item in the list and use a regular expression to select the ones that contain numbers
import re
def contains_num(inp):
return bool(re.search(r'\d', inp)) # Search for string containing numbers
with open("symbols.txt") as f:
symbols = f.read()
items = symbols.split()
ans = list(filter(contains_num, items))
Here's a way:
with open("YOURFILE") as file:
all_words = file.read().split()
words_containing_numbers = []
for word in all_words:
if any(char.isdigit() for char in word):
words_containing_numbers.append(word)
words_containing_numbers list not concatenate the word to it.+= will add each character in the string as a new element in the string.Quick one liner, just for fun, after import re:
list(filter(lambda w: re.search(r'\d', w), open("your-file.txt").read().split()))
