finding min and max in python

Question

Write a program that repeatedly prompts a user for integer numbers until the user enters 'done'. Once 'done' is entered, print out the largest and smallest of the numbers. If the user enters anything other than a valid number catch it with a try/except and put out an appropriate message and ignore it.

This is the question I have tried many ways but unable to achieve min and max numbers. Please help me with the code:

largest = None
samllest = None
while True:
    num = input("Enter Numbers:")
    if num == 'done' :
        break
    else:
        try:
            n = int(num)
        except:
            print("Invalid Input")

You seem to do a good job of taking and handling the input. Here's an idea: put all those numbers in a list, and when the user inputs done, use the built-ins min and max to return the relevant numbers — Tomerikoo
– Tomerikoo, Commented Nov 18, 2020 at 17:54
yep I taught of using the list but for that user need to mention the list size initially but I dont want that. Is there any other way. — Chaitanya Chitturi
– Chaitanya Chitturi, Commented Nov 18, 2020 at 17:56
Why would they need to do that? This is not C... Aren't you familiar with the list.append() method - appends x to the end of the sequence — Tomerikoo
– Tomerikoo, Commented Nov 18, 2020 at 17:58

Jussi Nurminen · Accepted Answer · 2020-11-18 20:49:55Z

1

Using the walrus operator for fun & brevity:

numbers = list()
while (the_input := input('Enter a number:')) != 'done':
    numbers.append(int(the_input))
print(f'{min(numbers)=}, {max(numbers)=}')

answered Nov 18, 2020 at 20:49

Jussi Nurminen

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Comments

Jasar Orion · Accepted Answer · 2020-11-18 17:55:48Z

0

you can do a list of inputed numbers:

numbers=[]
while True:
    num = input("Enter Numbers:")
    if num == 'done' :
        break
    else:
        try:
            numbers.append(int(num))
        except:
            print("Invalid Input")
print("Min", str(min(numbers)))
print("Max", str(max(numbers)))

you will have this result:

Enter Numbers:2
Enter Numbers:3
Enter Numbers:4
Enter Numbers:5
Enter Numbers:6
Enter Numbers:7
Enter Numbers:8
Enter Numbers:done
Min 2
Max 8

answered Nov 18, 2020 at 17:55

Jasar Orion

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2 Comments

Tomerikoo Over a year ago

No need to cast the print arguments to str - it is done automatically

Jasar Orion Over a year ago

yes your right. i have this mania to cast all elements.

Quinn · Accepted Answer · 2020-11-18 18:15:57Z

0

Here you re, probe it:

lg = None
sm = None
s = None

while s != 'done':
    s = input("Enter numbers:")
    if s.isdigit():
        s = int(s)
        if lg == None and sm == None:
            lg = s
            sm = s
            
        if lg <= s:
            lg = s
        if sm >= s:
            sm = s
            
print(f"Min: {sm}, Max: {lg}")

And you can test it:

Enter numbers:5
Enter numbers:6
Enter numbers:1
Enter numbers:5
Enter numbers:8
Enter numbers:9
Enter numbers:done
Min: 1, Max: 9

And if you want a try/except block...

lg = None
sm = None
s = None

while s != 'done':
    try:
        s = int(input("Enter numbers:"))
        if lg == None and sm == None:
            lg = s
            sm = s
            
        if lg <= s:
            lg = s
        if sm >= s:
            sm = s
            
    except Exception as e:
        print(e)
        
print(f"Min: {sm}, Max: {lg}")

edited Nov 18, 2020 at 18:15

answered Nov 18, 2020 at 18:05

Quinn

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1 Comment

Quinn Over a year ago

No problem, glad to help you ;). Please consider to mark it as correct answer.

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