In Python, how do I print integer one below the other:
a1 = "Great"
a2 = 100
for all in a1:
print(all)
Output:
G
r
e
a
t
Question: How do I write for/print statement for the variable a2, so that my output will be:
1
0
0
?
3 Answers
You need to convert a2, an int into something that is iterable. One way you could do this is by converting a2 into a string:
a2 = 100
for str_digit in str(a2): # if a2 is negative use str(a2)[1:] to not print '-' sign
print(str_digit)
And another way could be by extracting the individual digits (still as ints) from a2 into a list (or another iterable):
def get_digits(num):
num = abs(num)
digits = []
while num != 0:
digits.append(num % 10)
num //= 10
return digits
a2 = 100
for str_digit in get_digits(a2):
print(str_digit)
Output:
1
0
0
Comments
An object of type int is not iterable. So force it to be iterable by making it a string.
x = 1337
for num in str(x):
print(num)
Comments
To get letters of a word or elements of a number by a for loop you need a string
a = 100 is an integer so you need to convert it to a string like below :
a=str(100)
for i in a:
print(i)
Comments
for all in str(a2): print(all)intobjects aren't iterable, so convert it into some appropriate iterable object, e.g. astr