Sort array with mutiple arrays

Question

So I've made an array with the following values in it:

array = [[621, 685, '3'], [933, 618, '4'], [510, 392, '2'], [792, 280, '1']]

and these values are [x, y, number]. What I'm trying to do it to sort this array by the number value in each index, so that the array will look like this:

array = [[792, 280, '1'], [510, 392, '2'], [621, 685, '3'], [933, 618, '4']]

But how do I do this?

I've begun a function to make this, but I'm stuck

def sortNumbers(Cubes):

    print("array = ", Cubes)
    Cubes = np.split(Cubes, [0,2])
    for x in Cubes:
        print(x)

@ggorlen Thanks! now I get the right when I print print("array", sorted(Cubes, key=lambda x: int(x[2]))) didn't know I could do this! — Me NoLonely
– Me NoLonely, Commented Nov 25, 2020 at 23:40
Keep in mind that the ordering between strings that are numerical and numbers is not the same. Are you trying to treat them as strings or numbers? — ggorlen
– ggorlen, Commented Nov 26, 2020 at 1:36

AziMez · Accepted Answer · 2020-11-25 23:52:07Z

1

Hope this helped you.

array =  [[621, 685, '3'], [933, 618, '4'], [510, 392, '2'], [792, 280, '1']]
sorted_array = sorted(array, key=lambda kv: kv[2])
print(sorted_array)

[Result]

[[792, 280, '1'], [510, 392, '2'], [621, 685, '3'], [933, 618, '4']]

answered Nov 25, 2020 at 23:52

AziMez

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adrianoJose · Accepted Answer · 2020-11-26 00:05:58Z

1

I did some research and found something, and the code is

# of sublist Inplace way to sort using sort() 
def Sort(array): 

    # reverse = None (Sorts in Ascending order) 
    # key is set to sort using second element of 
    # sublist lambda has been used 
    array.sort(key = lambda x: x[2]) 
    return array 

# Driver Code 
array =  [[621, 685, '3'], [933, 618, '4'], [510, 392, '2'], [792, 280, '1']]
print(Sort(array))

here's a link if you wanna check more about it: https://www.geeksforgeeks.org/python-sort-list-according-second-element-sublist/

edited Nov 26, 2020 at 0:05

answered Nov 25, 2020 at 23:56

adrianoJose

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Me NoLonely · Accepted Answer · 2020-11-25 23:45:51Z

0

Credits to @ggorlen for awnsering this in the commends:

Solution

def sortNumbers(Cubes):
    Cubes = sorted(Cubes, key=lambda x: int(x[2]))
    print("Sorted array = ", sorted(Cubes, key=lambda x: int(x[2])))

    return Cubes

answered Nov 25, 2020 at 23:45

Me NoLonely

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Kirk Strauser · Accepted Answer · 2020-11-26 00:12:14Z

0

Python's operator module has a function itemgetter that does what you want. It creates a function that returns the Nth item (or items!) in the thing you pass to it. For example:

>>> from operator import itemgetter
>>> third = itemgetter(2)
>>> third(['a', 'b', 'c'])
'c'

That makes a wonderful key function for list.sort or sorted:

array.sort(key=itemgetter(2))  # In-place sorting
new_array = sorted(array, key=itemgetter(2))  # Create a new list

answered Nov 26, 2020 at 0:12

Kirk Strauser

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