How To use arrays in if statement corectly in Javascript

Question

i have pretty basic question. sorry for that. I'm trying to build result point system for test. but there is that problem everything is printing together. there is a code:

    var g_Point = [8,9,10];
    var n_Point = [5,6,7];
    var b_Point = [1,2,3,4];

    var my_Points = 10;
    if(my_Points === g_Point){
        document.write('You Got Really Good Point');
    }else if(my_Points === n_Point){
        document.write('You Got Normal Points');
    }else if(my_Points === b_Point){
        document.write('You Got Really Bad Points');
    }

A number isn't equal to an array, which is what you're testing. It's not totally clear what you're trying to do, but if as I suspect it's to test which array the number (10 here) is included in, you want the includes method — Robin Zigmond
– Robin Zigmond, Commented Nov 26, 2020 at 20:24
So i have a points from one to ten. i want to give definiton to my point as a text, if i got points from 8 to ten, i want to output specific text. that was the question. — Floyder
– Floyder, Commented Nov 26, 2020 at 20:27

Guerric P · Accepted Answer · 2020-11-26 20:25:07Z

2

You are not comparing two values, you want to check if a value is included in an Array, then use Array.prototype.includes():

var g_Point = [8, 9, 10];
var n_Point = [5, 6, 7];
var b_Point = [1, 2, 3, 4];

var my_Points = 10;
if (g_Point.includes(my_Points)) {
  document.write('You Got Really Good Point');
} else if (n_Point.includes(my_Points)) {
  document.write('You Got Normal Points');
} else if (b_Point.includes(my_Points)) {
  document.write('You Got Really Bad Points');
}

answered Nov 26, 2020 at 20:25

Guerric P

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