How to split a string AFTER every substring in Regex Python

Try

a=re.findall(r'(.*?\(ID\:\d{5}\))',text)
print(a)

output

['Company A, Inc(ID:12345)',
 ', some-company, X (ID:12324)',
 ', Some Special Company Z (ID:34324)']

Would you try the following:

import re
text = "Company A, Inc(ID:12345), some-company, X (ID:12324), Some Special Company Z (ID:34324)"

a = re.split(r'(?<=\(ID:\d{5}\)),\s*', text)
print(a)

Output:

['Company A, Inc(ID:12345)', 'some-company, X (ID:12324)', 'Some Special Company Z (ID:34324)']

Explanation of the regex r'(?<=\(ID:\d{5}\)),\s*':

• (?<=pattern) is a positive lookbehind assertion. It has the zero width and the matched substring remains in the split list.
• \(ID:\d{5}\) is the format as you describe.
• ,\s* matches a comma followed by a zero or more whitespace(s). We do not want to include the substring in the result and it works as a delimiter.

You can optionally match a comma and 1 or more whitespace chars. Then match at least a single non whitespace char for the company name until the first occurrence of the id pattern.

Note that you don't have to escape the \:

(?:,\s+)?(\S.*?\(ID:\d{5}\))

Explanation

• (?:,\s+)? Optionally match a comma and 1+ whitespace chars
• ( Capture group 1
  • \S.*? Match a non whitespace char followed by 0* as least as possible chars
  • \(ID:\d{5}\) Match (ID: 5 digits and )
• ) Close group

Regex demo | Python demo

Example

import re

text = "Company A, Inc(ID:12345), some-company, X (ID:12324), Some Special Company Z (ID:34324)"
print(re.findall(r"(?:,\s+)?(\S.*?\(ID:\d{5}\))", text))

Output

['Company A, Inc(ID:12345)', 'some-company, X (ID:12324)', 'Some Special Company Z (ID:34324)']