filter array object with array value

Question

I am trying to filter an array object with array value, here the code:

const array1 = [{
            "packaging": "Box",
            "price": "100"
        }, {
            "packaging": "Pcs",
            "price": "15",
        }, {
            "packaging": "Item",
            "price": "2",
        }];

const b = ['Pcs','Item']
const found = array1.filter(el => {
    for(i = 0; i < b.length; i++) {
      return el.packaging !== b[i];
    }
});

console.log(found);

my expected output is array with object doesnt not exist in b [{ packaging: "Box", price: "100" }]

Your nested for loop is unnecessary, .filter already loops over the elements. Do as the answers below say and just return the desired condition right away (using .includes) — Jayce444
– Jayce444, Commented Dec 11, 2020 at 5:34

CertainPerformance · Accepted Answer · 2020-12-11 05:33:21Z

4

Use an .includes check instead:

const array1 = [{
            "packaging": "Box",
            "price": "100"
        }, {
            "packaging": "Pcs",
            "price": "15",
        }, {
            "packaging": "Item",
            "price": "2",
        }];

const b = ['Pcs','Item']
const found = array1.filter(el => !b.includes(el.packaging));
console.log(found);

answered Dec 11, 2020 at 5:33

CertainPerformance

373k55 gold badges354 silver badges359 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Deadpool Over a year ago

That was a quick one using includes instead of b.indexOf(item) == -1. :) However, would you always suggest using includes ahead of old-fashioned way, in terms of performance? Or both are equal?

CertainPerformance Over a year ago

.includes might be a bit faster since it doesn't have to look at the index, just return a boolean - but what matters far more in real world situations is readability, 95% of the time, which .includes wins hands-down.

Md Sabbir Alam · Accepted Answer · 2020-12-11 05:33:30Z

0

You should do the following,

const array1 = [{
            "packaging": "Box",
            "price": "100"
        }, {
            "packaging": "Pcs",
            "price": "15",
        }, {
            "packaging": "Item",
            "price": "2",
        }];

const b = ['Pcs','Item']
const found = array1.filter(el => {
    return b.findIndex(item => item === el.packaging) <= -1;
});

console.log(found);

answered Dec 11, 2020 at 5:33

Md Sabbir Alam

5,0643 gold badges19 silver badges31 bronze badges

Comments

Deadpool · Accepted Answer · 2020-12-11 05:43:13Z

0

Does this solve your problem?

const arr1 = [
  {"packaging": "Box", "price": "100"}, 
  {"packaging": "Pcs", "price": "15"}, 
  {"packaging": "Item", "price": "2"}
];

const arr2 = ['Pcs','Item'];
const found = arr1.filter(item => {
  return arr2.indexOf(item.packaging) === -1;
});

console.log(found);

answered Dec 11, 2020 at 5:43

Deadpool

8,2969 gold badges49 silver badges96 bronze badges

Collectives™ on Stack Overflow

filter array object with array value

3 Answers 3

2 Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

2 Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related