python3: converting interger value(2byte) to two individual bytes in byte array

Question

I have following code which try to convert an integer value to two individual bytes in a bytearray.

value = 13183
print("Initial value: ", value)
val_msb = (value >> 8) & 0xFF
val_lsb = value & 0xFF
print("Value MSB:", val_msb, "Value LSB:", val_lsb)

val_arr = bytearray(2);
val_arr[0] = val_msb
val_arr[1] = val_lsb
print("Byte array:", val_arr)

Getting following output which is not matching with the expectation.

Initial value:  13183
Value MSB: 51 Value LSB: 127
Byte array: bytearray(b'3\x7f')

I expect it to produce final bytearray as Byte array: bytearray(b'x33\x7f')

Jim Danner · Accepted Answer · 2020-12-13 06:10:31Z

1

The character ’3’ has character code 51 (or 0x33). So what you’re seeing there, the 3, is not the numeric value but the character into which it is translated. If you make your last command

print(list(val_arr))

you can see that the values are correct.

answered Dec 13, 2020 at 6:10

Jim Danner

5652 silver badges13 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

python3: converting interger value(2byte) to two individual bytes in byte array

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related