Django - Python - How to include STATUS CODE in response using JsonResponse?

Question

Here is my code, that let users input their ID and Name to check if they are in a list of something.

def some_api(requests):
    try: 
        **do something**
        return HttpResponse('Your name is in the list') #Response 302 CODE FOUND NOT 202
    except:
        return JsonResponse([{ ID       : 123,         #Response 203 CODE EMPTY NOT 202
                               Name     : ABC,         #with information for users to double check
                               Content  : []           #their params
                              }])

As always, when I return HttpResponse and JsonResponse, it is always the 200 CODE

Richard Ochom · Accepted Answer · 2020-12-22 13:20:24Z

3

With django-rest-framework you can add status like below:

from rest_framework import status
from rest_framework.response import Response

@api_view()
def some_api(request):
  try:
     **do something**
     return Response('Your name is in the list', status=status.HTTP_302_FOUND)
  except:
    return Response({"id": 123, "Name": "Abc", "Content": []}, 
                     status=status.HTTP_203_NON_AUTHORITATIVE_INFORMATION)

edited Dec 22, 2020 at 13:20

answered Dec 22, 2020 at 10:10

Richard Ochom

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Guillaume · Accepted Answer · 2020-12-22 11:20:06Z

2

If you want to use the JsonResponse as said in your question.

JsonResponse({'status':'false','message':message}, status=500)

For HttpResponse, just use one of its subclasses: https://docs.djangoproject.com/en/3.1/ref/request-response/#httpresponse-subclasses.

Note that if you're using DRF, you should go for Ochom Richard's answer, rest_framework.response.Response object.

answered Dec 22, 2020 at 11:20

Guillaume

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