Async Function returning Undefined when calling it

Question

I'm Having some trouble with this function on a React project

let fetchData = async (event, imagen) => {
    const apiURL = `https://some_api_call/${imagen}`;
    await axios.get(apiURL).then((response) => {
      console.log(response.data.Imagen1.data);
      return response.data.Imagen1.data;
    });

When i call it the Console.log returns Undefined but the console log above returns the data

fetchData(event, rowData.Codigo).then(function (response) {
console.log(response);
});

Thank you for the comment, do you mean like " return await axios.get..."? — Tomás Méndez
– Tomás Méndez, Commented Dec 22, 2020 at 19:46
that indeed would return the promise and then you can use the .then or you can even let response=await fetchData(...args) — The Bomb Squad
– The Bomb Squad, Commented Dec 22, 2020 at 19:49

The Bomb Squad · Accepted Answer · 2020-12-22 19:48:07Z

1

let fetchData = async (event, imagen) => {
    const apiURL = `https://some_api_call/${imagen}`;
    return await axios.get(apiURL);
}
fetchData(event, rowData.Codigo).then(function (response) {
    console.log(response);
});

answered Dec 22, 2020 at 19:48

The Bomb Squad

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1 Comment

The Bomb Squad Over a year ago

ok i had a small syntax error.. it's fixed now

Bergi · Accepted Answer · 2020-12-22 21:22:01Z

1

Your fetchData function has no return statement. You probably don't want to use then when there is await:

async function fetchData(event, imagen) {
  const apiURL = `https://some_api_call/${imagen}`;
  const response = await axios.get(apiURL)
  console.log(response.data.Imagen1.data);
  return response.data.Imagen1.data;
}

answered Dec 22, 2020 at 21:22

Bergi

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