Sorted a list contains tuple in Python

Question

I have a list like this:

list = [('Betty', 42.5), ('Andrew', 46.5), ('Zach', 49), ('Cathy',     
42.5), ('Jay', 45.5), ('Kevin', 45), ('Cassie', 41), ('Matt', 44),     
('Jamie', 44.5), ('Xavier', 45.5), ('Peter', 45.5), ('John', 42.5), 
('Jamie', 40.5), ('Joe', 40.5), ('Ellen', 44.5), ('Nancy', 35), 
('Jay', 45), ('Bryce', 43.5), ('Gordon', 37), ('Gee', 42.5)]```

How I can sort it by name (if name is same, the one with higher score comes first) in Python?

I tried this but it doesn't sort by score if same name sorted(list)

Please do not use builtin names for variable names: list

anurag
– anurag

2020-12-30 06:36:03 +00:00
Commented Dec 30, 2020 at 6:36 — anurag
– anurag, Commented Dec 30, 2020 at 6:36
result = sorted(list) and the print(result)

D. Seah
– D. Seah

2020-12-30 06:38:06 +00:00
Commented Dec 30, 2020 at 6:38 — D. Seah
– D. Seah, Commented Dec 30, 2020 at 6:38

Hamza usman ghani · Accepted Answer · 2020-12-30 06:44:43Z

2

lst = [('Betty', 42.5), ('Andrew', 46.5), ('Zach', 49), ('Cathy', 42.5), ('Jay', 45.5), ('Kevin', 45), ('Cassie', 41), ('Matt', 44), ('Jamie', 44.5), ('Xavier', 45.5), ('Peter', 45.5), ('John', 42.5), ('Jamie', 40.5), ('Joe', 40.5), ('Ellen', 44.5), ('Nancy', 35), ('Jay', 45), ('Bryce', 43.5), ('Gordon', 37), ('Gee', 42.5)]

n0 = sorted(lst, key=lambda x: x[1],reverse=True) 
n1 = sorted(n0, key=lambda x: x[0])
print(n1)

edited Dec 30, 2020 at 6:44

Hamza usman ghani

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answered Dec 30, 2020 at 6:38

anurag

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1 Comment

Dai Vuong Over a year ago

Thank you, because it requires higher score first so I add reverse=True in n0. It works.

Paddy3118 · Accepted Answer · 2020-12-30 13:42:58Z

1

it is never good to re-use a name like list which already has a use in Python, so I changed it to data. If you negate numbers for sorting purposes, then although 40.5 is less than 44.5, -44.5 is less than -40.5, so if sorting would put the minimum number first, that same sort but on the negation of that numeric field puts the maximum first.

Here is that idea in action:

In [1]: data = [('Betty', 42.5), ('Andrew', 46.5), ('Zach', 49), ('Cathy',     
   ...: 42.5), ('Jay', 45.5), ('Kevin', 45), ('Cassie', 41), ('Matt', 44),     
   ...: ('Jamie', 44.5), ('Xavier', 45.5), ('Peter', 45.5), ('John', 42.5), 
   ...: ('Jamie', 40.5), ('Joe', 40.5), ('Ellen', 44.5), ('Nancy', 35), 
   ...: ('Jay', 45), ('Bryce', 43.5), ('Gordon', 37), ('Gee', 42.5)]

In [2]: sorted(data)
Out[2]: 
[('Andrew', 46.5),
 ('Betty', 42.5),
 ('Bryce', 43.5),
 ('Cassie', 41),
 ('Cathy', 42.5),
 ('Ellen', 44.5),
 ('Gee', 42.5),
 ('Gordon', 37),
 ('Jamie', 40.5),
 ('Jamie', 44.5),
 ('Jay', 45),
 ('Jay', 45.5),
 ('Joe', 40.5),
 ('John', 42.5),
 ('Kevin', 45),
 ('Matt', 44),
 ('Nancy', 35),
 ('Peter', 45.5),
 ('Xavier', 45.5),
 ('Zach', 49)]

In [3]: sorted(data, key=lambda x:(x[0], -x[1]))
Out[3]: 
[('Andrew', 46.5),
 ('Betty', 42.5),
 ('Bryce', 43.5),
 ('Cassie', 41),
 ('Cathy', 42.5),
 ('Ellen', 44.5),
 ('Gee', 42.5),
 ('Gordon', 37),
 ('Jamie', 44.5),
 ('Jamie', 40.5),
 ('Jay', 45.5),
 ('Jay', 45),
 ('Joe', 40.5),
 ('John', 42.5),
 ('Kevin', 45),
 ('Matt', 44),
 ('Nancy', 35),
 ('Peter', 45.5),
 ('Xavier', 45.5),
 ('Zach', 49)]

In [4]:

Jamie and Jay have there maximum number first without needing dual sorts and reversals.

answered Dec 30, 2020 at 13:42

Paddy3118

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2 Comments

anurag Over a year ago

This is great, more explanation at this link

Paddy3118 Over a year ago

... Except the linked article just states you can negate, with no extra help on why it works.

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