c initialize array and structs at the same time

Question

I'm trying to initialize both an array and the structs that it contains

#include <stdio.h>
#include <math.h>

typedef struct
{
    int  rgbtBlue;
    int  rgbtGreen;
    int  rgbtRed;
} __attribute__((__packed__))
RGBTRIPLE;

void edges(int height, int width, RGBTRIPLE image[height][width]);

int main()
{
    int height = 3;
    int width = 3;
    RGBTRIPLE image[height][width] = {
        {{0, 10, 25}, {0, 10, 30}, {40, 60, 80}},
        {{20, 30, 90}, {30, 40, 100}, {80, 70, 90}},
        {{20, 20, 40}, {30, 10, 30}, {50, 40, 10}}
    };
    return 0;
}

I'm not sure whether this initialization can happen at the same time or if I must initialize first all the structs before inserting them into the array.

Do you get an error when you compile?

stark
– stark

2021-01-07 15:47:47 +00:00
Commented Jan 7, 2021 at 15:47 — stark
– stark, Commented Jan 7, 2021 at 15:47

Eric Postpischil · Accepted Answer · 2021-01-07 15:48:14Z

You can give initial values for the elements in an array, including members of structures in the array, when defining an array.

The C standard says a thing being initialized shall not have variable length array type (C 2018 6.7.9 3). Your array has variable length array type because height and width are variables, not constants as C defines them. To fix that, you can use #define directives or enum declarations to define height and width.

If you do need a variable length array or a dynamically allocated array, you can give values to its elements using assignment statements, including assignments of whole structures using a compound literal for each structure, as in:

image[i][j] = (RGBTRIPLE) { 0, 10, 25 };

However, the C standard does not provide any way to give initial values to a variable length array or dynamically allocated array during its creation. With optimization, assigning values immediately after creating an array will likely be equivalent to initializing them during creation.

Adrian Mole · Accepted Answer · 2021-01-07 15:49:49Z

0

The problem in your code is not due to the fact that you have an array of structures; rather, it is because it is a variable length array (VLA), and VLAs cannot be initialized.

To fix this (assuming you are using a GCC-compatible compiler, as hinted by your use of __attribute__((__packed__))), you can declare the height and width 'variables' as const:

int main()
{
    const int height = 3;
    const int width = 3;
    RGBTRIPLE image[height][width] = {
        {{0, 10, 25}, {0, 10, 30}, {40, 60, 80}},
        {{20, 30, 90}, {30, 40, 100}, {80, 70, 90}},
        {{20, 20, 40}, {30, 10, 30}, {50, 40, 10}}
    };
    for (int h = 0; h < height; ++h) {
        for (int w = 0; w < width; ++w) {
            printf("%3d %3d %3d | ", image[h][w].rgbtBlue, image[h][w].rgbtGreen, image[h][w].rgbtRed);
        }
        printf("\n");
    }
    return 0;
}

This will compile, but with warnings:

warning : variable length array folded to constant array as an extension [-Wgnu-folding-constant]

answered Jan 7, 2021 at 15:49

Adrian Mole

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2 Comments

user694733 Over a year ago

Sizes could be declared as enum { width=3, height=3 }; to avoid compiler extensions.

Adrian Mole Over a year ago

@user694733 Of course. But Eric had already posted that by the time I had posted my answer, so adding that option would have been 'stealing' his (excellent) answer. So I didn't do it.

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