Why selenium not recognizing class in Python?

Question

Selenium is not recognizing the class. I was trying to click an audio button on a website using selenium but it is not recognizing this class

class="jumbo--Z12Rgj4 buttonWrapper--x8uow audioBtn--1H6rCK"

Here is my code

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
options = webdriver.ChromeOptions() 
options.add_argument(r"user-data-dir=./c")

driver=webdriver.Chrome(executable_path=r"C:\Users\Users\Desktop\Scrapping\chromedriver.exe",options=options)
    
driver.get(r"https://www.xx------xx.com")
    
button5 = driver.find_element_by_class_name(r"jumbo--Z12Rgj4")
    
button5.click()

But selenium is throwing an exception

jumbo--Z12Rgj4

Exception:

selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":".label--Z12LMR3"}

Should get logged in to get through the site, it's my college online class website. — Vikas Konaparthi
– Vikas Konaparthi, Commented Jan 8, 2021 at 8:57

user1734234 · Accepted Answer · 2021-01-08 08:56:29Z

1

If you check again, there would be more than one class 'jumbo--Z12Rgj4', hence selenium is throwing exception. To make it more dynamic, better use xpath with "contains(@class,'jumbo--Z12Rgj4')", followed by another identifier to make the search unique.

answered Jan 8, 2021 at 8:56

user1734234

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2 Comments

Vikas Konaparthi Over a year ago

Can you show me the syntax for Xpath using class

Vikas Konaparthi Over a year ago

selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//div[@class='label--Z12LMR3']"} (Session info: chrome=87.0.4280.88)

Arvind Raghu · Accepted Answer · 2021-01-08 08:59:59Z

1

The element that you wish to target probably has a uniquely hashed classname every time you load it, because it is not being found at all on the website, so rather than using the classname, try to use its xpath instead.

answered Jan 8, 2021 at 8:59

Arvind Raghu

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2 Comments

Vikas Konaparthi Over a year ago

Can you show me the syntax for Xpath using class

Vikas Konaparthi Over a year ago

selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//div[@class='label--Z12LMR3']"} (Session info: chrome=87.0.4280.88)

undetected Selenium · Accepted Answer · 2021-01-08 12:52:46Z

The value of class attribute i.e. jumbo--Z12Rgj4 buttonWrapper--x8uow audioBtn--1H6rCK is dynamic and will keep on changing everytime you access the application. To click on the element with text as save you can use either of the following Locator Strategies:

Using css_selector:

driver.find_element_by_css_selector("[class^='jumbo']").click()

Using xpath:

driver.find_element_by_xpath("//*[starts-with(@class, 'jumbo')]").click()

Ideally, to click on the element you need to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies:

Using CSS_SELECTOR:

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "[class^='jumbo']"))).click()

Using XPATH:

WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//*[starts-with(@class, 'jumbo')]"))).click()

Note: You have to add the following imports :

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

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