I would like something doing the following:
s = "abc"
print (func(s))
Ouput:
s
I've seen it seems not possible to do so, but still I try if someone knows
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4Why do you want to do this?juanpa.arrivillaga– juanpa.arrivillaga2021-01-19 06:01:29 +00:00Commented Jan 19, 2021 at 6:01
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4Possibly relevant: xyproblem.infocostaparas– costaparas2021-01-19 06:01:53 +00:00Commented Jan 19, 2021 at 6:01
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Essentially to read the code behind and to see how that could be possible.Math27– Math272021-01-19 06:15:03 +00:00Commented Jan 19, 2021 at 6:15
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2 Answers
from varname import nameof
s = 'abc'
print (nameof(s))
Output:
s
Package here:
https://github.com/pwwang/python-varname
Well, it is feasible, which does not mean it should be done. There is no difference with a print ("s") practically, plus there is dict if you want to associate a key and a value.
4 Comments
Julien
I fail to see how
nameof(s) is any better than "s"...
Synthaze
Yes right sorry. Well it is certainly useless, still it is funny.
Panwen Wang
You should actually use
argname() in such a case. See my answer to this question. BTW, I am the author of the python-varname package.Synthaze
@PanwenWang what a provocative work you did!
from varname import argname
def func(s):
# if varname version < 0.7.2
# name = argname(s)
name = argname('s')
print(name, '=', s)
a = 1
b = 2
func(a) # a = 1
func(b) # b = 2
Disclaimer: I am the author of the python-varname package.
