Splitting Class into its Attributes in Lambda Expression in Java

Question

Let's say you have a custom class:

public class T {
    int a;
    int b;
}

Is there a way you can split up the class in a lambda expression in the following way:

(Stream of T instances).forEach((a, b) -> {});

stream.forEach(t -> {... t.a ... t.b ...});?

Eran
– Eran

2021-01-25 08:57:37 +00:00
Commented Jan 25, 2021 at 8:57 — Eran
– Eran, Commented Jan 25, 2021 at 8:57
No, you cannot use a BiConsumer this way natively.

sp00m
– sp00m

2021-01-25 09:05:07 +00:00
Commented Jan 25, 2021 at 9:05 — sp00m
– sp00m, Commented Jan 25, 2021 at 9:05
What are you actually trying to achieve?

tgdavies
– tgdavies

2021-01-25 09:11:31 +00:00
Commented Jan 25, 2021 at 9:11 — tgdavies
– tgdavies, Commented Jan 25, 2021 at 9:11

Aniket Sahrawat · Accepted Answer · 2021-01-25 09:09:53Z

2

Java doesn't have the concept of tuples, so no! But there can be a workaround by converting the stream to a Map (which has a lot of limitations and consequences):

(Stream of T instances)
    .collect(Collectors.toMap(t -> t.a, t -> t.b))
    .forEach((a, b) -> {});

answered Jan 25, 2021 at 9:09

Aniket Sahrawat

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2 Comments

Naman Over a year ago

why convert to a Map even? and what limitations and consequences are related to OP's problem?

Aniket Sahrawat Over a year ago

@Naman I certainly don't need to justify the limitations of converting stream to a map. You are free to post an answer that has BiConsumer rather than criticizing my post(as always).

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