$var1 = 'abc';
$var2 = '123';
How can I replace %var1 and %var2% from a string like this:
aaaaaaaa%var1%bbbbbbbbb%var2%ffffffff
with the value of $var1 and $var2 ?
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2whaaaaaaat -2 ?? fuuuuuuuuuuufoo– foo2011-07-05 23:40:19 +00:00Commented Jul 5, 2011 at 23:40
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3 Answers
Assuming >= PHP 5.3...
preg_replace_callback('%(\w+?)%', function($matches) use ($var1, $var2) {
return $$matches[1][0];
}, $str);
As you can see, you need to pass a reference to each of the outer variables to the closure.
You are probably better constructing an array with the replacement variables, and just passing that array in and then subscripting it...
preg_replace_callback('%(\w+?)%', function($matches) use ($vars) {
return isset($vars[$matches[1][0]]) ? $vars[$matches[1][0]] : $matches[0][0];
}, $str);
I haven't got a chance to test this code right now, but I believe the general principle is sound :)
1 Comment
foo
can you post a example of how would I pass the array? do I replace the function() with it?
$var1 = 'abc';
$var2 = '123';
$subject = 'aaaaaaaa%var1%bbbbbbbbb%var2%ffffffff';
echo str_replace(array('%var1%', '%var2%'), array($var1, $var2), $subject);
// output: aaaaaaaaabcbbbbbbbbb123ffffffff
Comments
If I'm reading your question correctly, you want to take the string literal
'aaaaaaaa%var1%bbbbbbbbb%var2%ffffffff' and replace the substrings var1 and var2 with 'abc' and '123', respectively, right? In that case, preg_replace should do the trick.