How to create new JS array from another JS array

Question

I want to create new JS array from an object. I explained my scenario as below.

Array 1:

const arr1 = [
  {CODE: "PPM", YARN: 1987, EXP: "IUYT", CARD: "MMN"},
  {CODE: "SSW", YARN: 4500, EXP: "NBVC", CARD: "MMN"},
  {CODE: "YTR", YARN: 0740, EXP: "NBVC", CARD: "MMN"},
  {CODE: "NNH", YARN: 1540, EXP: "MHYT", CARD: "MMN"}
]

Array 2:

const arr2 = [
  {PRICE: 6354, CODE: "SSW", WARN: "NBVC"},
  {PRICE: 8637, CODE: "NNH", WARN: "MHYT"},
]

Expected output:

output = [
  {CODE: "SSW", YARN: 4500, EXP: "NBVC", CARD: "MMN"},
  {CODE: "NNH", YARN: 1540, EXP: "MHYT", CARD: "MMN"}
]

Explanation:

I want to compare arr1 and arr2. If arr1.code contain arr2.code it should be in new array. It means arr1.code[2] = 'SSW'. SSW contains in arr2.code[0]. Then arr1.code[2] should be in new array. It same to arr1.code[3] = 'NNH'. NNH contains in arr2.code[1].

Tried code:

console.log(arr1.filter(({ CODE: code1 }) => arr2.some(({ CODE: code2 }) => code2 === code1));

When I tried to above code I am getting an error

Error in render: "TypeError: Cannot read property 'price' of undefined"

Help me to solve this problem.

price isn't doesn't appear in your code. Also, js is case sensitive — Chayim Friedman
– Chayim Friedman, Commented Jan 28, 2021 at 18:28
@ChayimFriedman yeah js is case sensitive I fixed it in code. How can I skip PRICE and consider only CODE — aer-der
– aer-der, Commented Jan 28, 2021 at 18:31
Your code works when I run it, only add ) in the end of it — Ravid
– Ravid, Commented Jan 28, 2021 at 18:31
@aer-der What do you mean by "skip PRICE"? Where are you even using PRICE in your code? — gen_Eric
– gen_Eric, Commented Jan 28, 2021 at 18:32
@Ravid can you please post it in jsfiddle. Because It not gives a output for me — aer-der
– aer-der, Commented Jan 28, 2021 at 18:33

Hussain · Accepted Answer · 2021-01-28 18:50:50Z

5

const arr1 = [
  {CODE: "PPM", YARN: 1987, EXP: "IUYT", CARD: "MMN"},
  {CODE: "SSW", YARN: 4500, EXP: "NBVC", CARD: "MMN"},
  {CODE: "YTR", YARN: 0740, EXP: "NBVC", CARD: "MMN"},
  {CODE: "NNH", YARN: 1540, EXP: "MHYT", CARD: "MMN"}
]

const arr2 = [
  {PRICE: 6354, CODE: "SSW", WARN: "NBVC"},
  {PRICE: 8637, CODE: "NNH", WARN: "MHYT"},
]

console.log(arr1.filter(({
    CODE: code1
}) => arr2.some(({
    CODE: code2
}) => code2 === code1))**)**;

I guess you might have missed a bracket ) in the console.log statement. But still, you have not used the price keyword in the code. Might be some other issue. Can you please share the full function?

answered Jan 28, 2021 at 18:50

Hussain

1,7431 gold badge10 silver badges10 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

How to create new JS array from another JS array

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related