Problem accessing global variable in javascript

Question

I am working on google maps and I need to create an array of items. Here is my pseudo code:

<script>
var myvar=new array();

function initialize(){
   for i=1 to 10
   {  
        callAnotherFunct(i);
   }

   access myvar() here; 
}


function callAnotherFunct(i){
    myvar=array_element_i;
}

</script>

I am expecting myvar to behave as a global variable but it is not. I cannot get any values for myvar in the initialize().

What am I doing wrong here?

Can we see the actual code, please? It may help spot the problem — James Long
– James Long, Commented Jul 6, 2011 at 18:30
is this pseudocode? bc if this is your real code it wont do anything, it is completely wrong — Naftali
– Naftali, Commented Jul 6, 2011 at 18:31
Why not post real code? What's the thinking behind providing us with a mangled version of something that you must surely have tried in real JavaScript? — Kerrek SB
– Kerrek SB, Commented Jul 6, 2011 at 18:32
var myGlobalVar = {} and then use something like myGlobalVar.myArray = new Array() Probably a namespace collision. I had the same issue and using a separate namespace seemed to work :) — PhD
– PhD, Commented Jul 6, 2011 at 18:35

Briguy37 · Accepted Answer · 2011-07-06 18:38:15Z

2

pseudo-schmeudo.

var myvar = [];

function initialize(){
   for (var i=0; i < 10; i++)
   {  
        callAnotherFunct(i);
   }

   alert(myvar[0]);
   alert(myvar[9]);
}


function callAnotherFunct(i){
    myvar[i]=i + 'pseudo-schmeudo';
}

initialize();

Fiddle-schmiddle.

answered Jul 6, 2011 at 18:38

Briguy37

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Comments

Kevin Bowersox · Accepted Answer · 2011-07-06 18:36:39Z

1

I am not sure what you were trying to accomplish, but I was able to make several modifications and was able to access the global variable in this example: http://jsfiddle.net/pKU6A/

var myvar=new Array(); //Array should be uppercase

function initialize(){
   for (var i=1; i < 10; i++) //incorrect for loop syntax
   {  
        callAnotherFunct(i);
   }

  alert(myvar);
}


function callAnotherFunct(i){
    myvar[i] = i; //local variable was not defined and index of array must be assigned
}

initialize(); //needed to call global function to kick it off

answered Jul 6, 2011 at 18:36

Kevin Bowersox

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Igor Dymov · Accepted Answer · 2011-07-06 18:33:49Z

1

fiddle: http://jsfiddle.net/AKKHB/

Seems to be ok

answered Jul 6, 2011 at 18:33

Igor Dymov

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Comments

Sebastian Ryszard Kruk · Accepted Answer · 2011-07-06 18:44:34Z

1

It is hard to tell what you might be doing wrong - with the pseudocode.

I have de-pseudified your code and it works fine:

var myvar=new Array();

function initialize(){
  for (i=1; i < 10; i++)
  {  
    callAnotherFunct(i);
  }
  alert(myvar);
  //access myvar() here; 
}

function callAnotherFunct(i){
  myvar.push(i);
}

when you call initialize() - it will alert with 1,2,3,4,5,6,7,8,9

Hope that helps

edited Jul 6, 2011 at 18:44

answered Jul 6, 2011 at 18:35

Sebastian Ryszard Kruk

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Comments

Pablo Fernandez · Accepted Answer · 2011-07-06 18:34:38Z

0

window.myvar = []; // don't use new Array()

function initialize(){
   for i=1 to 10
   {  
        callAnotherFunct(i);
   }

   //window.myvar or myvar here should work
}

answered Jul 6, 2011 at 18:34

Pablo Fernandez

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Comments

Soatl · Accepted Answer · 2011-07-06 18:40:03Z

0

I am guessing this is a namespace issue. Do something like this

window.project = window.project || {};
project.vars = project.vars || {};

Then you will have a namespace declaration, so you can do

project.vars.myVar = new Array();

That's the only issue I could think of

answered Jul 6, 2011 at 18:40

Soatl

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