How to do Typescript regex replace and extract value in the same time?

Question

I'd like to change path = 'a.0.b.c.e.f.11.d.20' to 'a[0].b.c.e.f[11].d[20]'

I was thinking to use something like : replace(/\.\d+/g , '.[${d+}]');

But this is not working. How can I replace the .number with with value .[number]?

CertainPerformance · Accepted Answer · 2021-02-03 05:47:26Z

2

After matching a period, capture digits in a group, then replace with those digits in brackets using the capture group:

console.log(
  'a.0.b.c.e.f.11.d.20'
    .replace(/.(\d+)/g, '[$1]')
);

answered Feb 3, 2021 at 5:47

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