PHP How to display some values of multidimensional array with for loop

Question

I loop through a multidimensional array to echo the first five values of every "row" as a table. As far as that, it works perfectly:

"<table>";
for ($row = 0; $row < $index_number; $row++) {
  echo  "<tr>";
  for ($col = 0; $col < 5; $col++) {
   echo "<td>".$tablevalue[$row][$col]."</td>";
  }
echo "</tr>";
}
echo"</table>";

Now I want to display numbers 1 to 3 and then 8 and 9 again. Neither one for loop inside another nor two seperate loops work the way I want them to.
Thats what I tried so far:

echo "<table>";
for ($row = 0; $row < $index_number; $row++) {
  echo  "<tr>";
  for ($col = 0; $col < 3; $col++ && $col2 = 8; $col2 < 10; $col2++) {
   echo "<td>".$tablevalue[$row][$col]."</td>";
  }
echo "</tr>";
}
echo"</table>";

Any ideas on how to make it work?

Did you give up?

AbraCadaver
– AbraCadaver

2021-03-02 04:24:35 +00:00
Commented Mar 2, 2021 at 4:24 — AbraCadaver
– AbraCadaver, Commented Mar 2, 2021 at 4:24

AbraCadaver · Accepted Answer · 2021-02-10 21:34:28Z

1

For your inner loop just use a conditional, if you have integer indexes starting at 0:

foreach($tablevalue[$row] as $col => $val) {
    if($col < 3 || ($col > 7 && $col < 10)) {
        echo "<td>$val</td>";
    }
}

However, as you can see foreach is much easier for the entire thing:

foreach($tablevalue as $row) {
    echo "<tr>";
    foreach($row as $col => $val) {
        if($col < 3 || ($col > 7 && $col < 10)) {
            echo "<td>$val</td>";
        }
    }
    echo "</tr>";
}

If you don't have integer indexes starting at 0, then just foreach(array_values($tablevalue)... and foreach(array_values($row)... or you can slice what you want and implode:

foreach($tablevalue as $row) {
    echo "<tr><td>";
    echo implode("</td><td>", array_slice($row, 0, 3, true) + 
                              array_slice($row, 7, 2, true));
    echo "</td></tr>";
}

edited Feb 10, 2021 at 21:34

answered Feb 10, 2021 at 20:53

AbraCadaver

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