The result of this code is different depend on type of reference variable does this mean variables (int a) are bounded in static way
class A{
int a = 10;
}
public class Main extends A {
int a = 30;
public static void main(String[] args){
A m = new Main();
System.out.println("A : " + m.a);
}
}
This is not just like static or dynamic binding. There is no polymorphism for fields in Java, only for methods.
Variables decisions are always taken at compile-time.
So, during the upcasting base class variable will be taken.
The variable m you have declared is of type A so the output would be 10. Instead if you have initialized m as Main m = new Main();, then the output would have been 30. This is because, the object is of type Main and since Main also has a field a, this would override the parent field a.
You have two object's type (A, Main) both from them have their own meaning for a variable a, so when your variable m has type A you get value 10 and if variable m has type Main you will get value 30.
