I have a hash
h = {a=> 1, b=> 2, c=> 3}
and an array
a = [a, b]
Is it possible to use
h.select {|k,v| k == array_here?}
To select all elements from the array that exists in the hash?
I Found the Solution
h.select {|k,v| a.include?(k) }
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You should add your solution as an answer and accept itVincent Robert– Vincent Robert2011-07-08 09:19:43 +00:00Commented Jul 8, 2011 at 9:19
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You are asking for "all elements from the array that exist in the hash", but instead wanting "all elements from the hash whose keys exist in the array". The question was misleading and resulted with wrong answers.Mladen Jablanović– Mladen Jablanović2011-07-08 12:30:22 +00:00Commented Jul 8, 2011 at 12:30
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I think is the same. all elements from the array that exist in the hash has the same meaning as all elements from the hash whose keys exist in the array!glarkou– glarkou2011-07-08 12:34:14 +00:00Commented Jul 8, 2011 at 12:34
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2It is not. In your solution you will get an array of [k, v] in R1.8, a hash in R1.9. This is definitely not the same as elements of an array.Victor Moroz– Victor Moroz2011-07-08 13:42:30 +00:00Commented Jul 8, 2011 at 13:42
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4 Answers
You could achieve that with something like:
a.each do |arr_elem|
new_hash[arr_elem] = h[arr_elem] unless h[arr_elem].nil?
end
Comments
If you really want what you have asked (i. e. elements of an array which present as keys in a hash):
h = {:a => 1, :b => 2, :c => 3}
a = [:a, :b, :d]
a & h.keys
Comments
One possible and the easiest answer is:
h.select {|k,v| a.include?(k) }