Python continue if xml element name is not present

Question

There are 2 kinds of XML output I may get-

Output 1:

<?xml version="1.0" encoding="UTF-8"?>
<BESAPI xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="BESAPI.xsd">
    <Action>
        <ActionID>123</ActionID>
    </Action>
</BESAPI>

Output 2:

<?xml version="1.0" encoding="UTF-8"?>
<BESAPI xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="BESAPI.xsd">
    <Action>
        <ActionID>789</ActionID>
        <Computer ID="456">
            <Status>The action is successful.</Status>
        </Computer>
    </Action>
</BESAPI>

I want to print Computer Status to a list if present. If not, print Action ID.

This is the code I have but it does not give any result for XML Output 1-

import xml.etree.ElementTree as ET
actionstatuslist = []
doc = ET.parse('actionstatus.xml')
root = doc.getroot()

for elem in root.findall('.//Computer'):
    for subelem in elem.findall('Status'):
        if subelem is None:
            for el in root.iter('Action'):
                for subel in el.iter('ActionID'):
                    actionid = int(subel.text)
                    print(actionid)
        else:
            actionstatuslist.append(subelem.text)

Desired result for XML Output 1-

I'm getting the correct Computer Status result for XML Output 2 though-

'The action is successful.'

I need help with Output 1 scenario.

@OsadhiVirochana - I get: [<Element 'Status' at 0x7feafe0ab850>] — jenhenry
– jenhenry, Commented Feb 15, 2021 at 5:50

Osadhi Virochana · Accepted Answer · 2021-02-15 09:14:29Z

1

Because of root.findall('.//Computer') returns empty list([]) it doesn't execute

for elem in root.findall('.//Computer'):
    for subelem in elem.findall('Status'):
        if subelem is None:
            for el in root.iter('Action'):
                for subel in el.iter('ActionID'):
                    actionid = int(subel.text)
                    print(actionid)
        else:
            actionstatuslist.append(subelem.text)

So at first, you need to check if root.findall('.//Computer') is empty and then check if elem.findall('Status') is empty. If one if them are empty then run

for el in root.iter('Action'):
    for subel in el.iter('ActionID'):
        actionid = int(subel.text)
        print(actionid)

It is easier if you use it as a function

Final code will be like this:

import xml.etree.ElementTree as ET
actionstatuslist = []
doc = ET.parse('actionstatus.xml')
root = doc.getroot()

def get_action_id():
    for el in root.iter('Action'):
        for subel in el.iter('ActionID'):
            actionid = int(subel.text)
            print(actionid)
    

if root.findall('.//Computer'):
    for elem in root.findall('.//Computer'):
        if elem.findall('Status'):
            for subelem in elem.findall('Status'):
                actionstatuslist.append(subelem.text)
        else:
            get_action_id()               
else:    
    get_action_id()

Edit in final code(Added requested features in comments):

import xml.etree.ElementTree as ET
actionstatuslist = []
doc = ET.parse('actionstatus.xml')
root = doc.getroot()

def get_action_id():
    for el in root.iter('Action'):
        for subel in el.iter('ActionID'):
            actionid = int(subel.text)
            print(actionid)
    
get_action_id()
for elem in root.findall('.//Computer'):
    if elem.findall('Status'):
        for subelem in elem.findall('Status'):
            actionstatuslist.append(subelem.text)
            print(elem.get('ID'))

edited Feb 15, 2021 at 9:14

answered Feb 15, 2021 at 6:26

Osadhi Virochana

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10 Comments

jenhenry Over a year ago

Thank you, that worked!! How do I also print the ActionID from XML Output 2? Right now it only prints the status. I want its corresponding ID. Desired output - 789 and 456

Osadhi Virochana Over a year ago

You can get ActionID by adding nope() after actionstatuslist.append(subelem.text). Can you mention what do you want to do so I can write a better code?

jenhenry Over a year ago

For Output 1: Desired output - 123 (This works now) For Output 2: Desired output - 789 456

Osadhi Virochana Over a year ago

@jenhenry I changed the code as you mentioned.

jenhenry Over a year ago

Thanks but the edited code only provides computer ID 456. I want 789 also...

|

Ajay · Accepted Answer · 2021-02-15 15:36:38Z

1

import xml.etree.ElementTree as ET
actionstatuslist = []
doc = ET.parse('actionstatus.xml')
root = doc.getroot()

for child in root.iter('Action'):
    grand_child=child.find("Computer/Status")
    if grand_child != None:
        actionstatuslist.append(grand_child.text)
    else:
        temp=child.find("ActionID")
        actionstatuslist.append(temp.text)

First we've got the Action tag inside child and we are looking for Computer/Status,using a if or we are going to just get the ActionID .

answered Feb 15, 2021 at 15:36

Ajay

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