#include <stdio.h>
int main()
{
int a[] = {1, 2, 3};
printf("%d", 0[a]);
printf("\n%d", 2[a]);
return 0;
}
Output:
1
3
I know how to access the array element with the index, but how this above syntax accessing the first value in both scenarios and add the prefixed numbers?
In C, the arrays and pointers have similarities. When you access an array element array[3]. This is equivalent to:
*(array + 3) // Dereferencing the 3rd index from beginning
Similarly, when you try to access it like 3[array], the statement goes like:
*(3 + array) // Identical to the first example
Which is identical. Lastly, when you want to obtain the N-th element of an array N[array], the syntax becomes:
*(N + array)
That's why you get your expected output.