I have a problem with string, I am aware that using isdigit() we can find whether an integer in the string is an int or not but how to find when its float in the string. I have also used isinstance() though it didn't work. Any other alternative for finding a value in the string is float or not??
My code:
v = '23.90'
isinstance(v, float)
which gives:
False
Excepted output:
True
You could just cast it to float or int, and then catch an eventual exception like this:
try:
int(val)
except:
print("Value is not an integer.")
try:
float(val)
except:
print("Value is not a float.")
You can return False in your except part and True after the cast in the try part, if that's what you want.
Maybe you can try this
def in_float_form(inp):
can_be_int = None
can_be_float = None
try:
float(inp)
except:
can_be_float = False
else:
can_be_float = True
try:
int(inp)
except:
can_be_int = False
else:
can_be_int = True
return can_be_float and not can_be_int
In [4]: in_float_form('23')
Out[4]: False
In [5]: in_float_form('23.4')
Out[5]: True
A really simple way would be to convert it to float, then back to string again, and then compare it to the original string - something like this:
v = '23.90'
try:
if v.rstrip('0') == str(float(v)).rstrip('0'):
print("Float")
else:
print("Not Float")
except:
print("Not Float!")
You can check whether the number is integer or not by isdigit(), and depending on that you can return the value.
s = '23'
try:
if s.isdigit():
x = int(s)
print("s is a integer")
else:
x = float(s)
print("s is a float")
except:
print("Not a number or float")
s = "text" ?
