Java Get request with parameter and Authetification

Question

I woudlike to put some parameter in my request (code value and name value) :

    String code = "001";
    String name = "AAA";       

    HttpGet request = new HttpGet(url);
    String auth = user + ":" + mdp;

    byte[] encodedAuth = Base64.encodeBase64(
            auth.getBytes(StandardCharsets.ISO_8859_1));

    String authHeader = "Basic " + new String(encodedAuth);

    request.setHeader(HttpHeaders.AUTHORIZATION, authHeader);

    HttpClient client = HttpClientBuilder.create().build();
    HttpResponse response = client.execute(request);

    int statusCode = response.getStatusLine().getStatusCode();

How can I do this with authentification request ?

Something like : code=001&name=AAA in the URL

Add the parameters to url, e.g., url += "?" + code=001&name=AAA". This is somewhat ugly, so there are probably (hopefully) more elegant ways to build the string used in HttpGet. Those parameters should also be properly encoded. — Andrew S
– Andrew S, Commented Mar 8, 2021 at 13:11
@AndrewS Thank you very much ! that's exactly what I'm looking for ! — Software14
– Software14, Commented Mar 8, 2021 at 13:19

Dropout · Accepted Answer · 2021-03-08 13:38:29Z

0

Use a URIBuilder to construct your URL

import org.apache.http.client.utils.URIBuilder;
//...
final String URI_PARAM_CODE = "code";
final String URI_PARAM_NAME = "name";

String code = "001";
String name = "AAA";

URI uri = new URIBuilder("http://google.com")
    .setParameter(URI_PARAM_CODE, code)
    .setParameter(URI_PARAM_NAME, name)
    .build();

You can also set other useful attributes before calling URIBuilder::build - please refer to Apache URIBuilder documentation.

answered Mar 8, 2021 at 13:38

Dropout

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