Filter array by property and other array

Question

I have a planning, with multiple items. My object is like this :

planning: [
  { id: '1', equipe: [ '1', '2' ] },
  { id: '2', equipe: [ '1' ] },
  { id: '3', equipe: [ '2', '3' ] }
  ...
]

I want to filter this array to hide or show planning items. My shown array is :

checked: [ '1', '4' ]

So, the array planning could be filtered by equipe array, so it should be :

planning: [
  { id: '1', equipe: [ '1', '2' ] },
  { id: '2', equipe: [ '1' ] }
]

I've tried to filter array but I don't see how indexOf could work with array and not string. I've also tried includes function but this doens't work:

planning.filter(item => checked.includes(item.equipe))

Thask for help !

planning.filter(item => checked.includes(item.equipe)) In this you are not checking if any element from checked array is present within the equipe instead you are checking whether checked contains the equipe array itself. — Rajiv Punjabi
– Rajiv Punjabi, Commented Mar 17, 2021 at 17:56

Rafael Buzatto de Campos · Accepted Answer · 2021-03-17 18:23:13Z

1

you need iterate over each value from item.equipe against checked, you could use some to check if at least one matches checked array:

planning.filter(item => item.equipe.some(val => checked.includes(val)))

const planning = [
  { id: '1', equipe: [ '1', '2' ] },
  { id: '2', equipe: [ '1' ] },
  { id: '3', equipe: [ '2', '3'] }
]
   
const checked = [ '1', '4' ]
   
const filtered = planning.filter(item => item.equipe.some(val => checked.includes(val)))
   
console.log(filtered)

edited Mar 17, 2021 at 18:23

answered Mar 17, 2021 at 17:57

Rafael Buzatto de Campos

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Rajiv Punjabi · Accepted Answer · 2021-03-17 18:39:11Z

I would implement the logic in this manner.

//Original Data
let planning = [
    { id: '1', equipe: ['1', '2'] },
    { id: '2', equipe: ['1'] },
    { id: '3', equipe: ['2', '3'] }
]

/**
 * Converting checked into Set so it will maintain all the unique values.
 * I can check which elements are present in O(1) using checked.has(value)
 */
let checked = new Set(['1', '4'])


/**
 * Using standard filter() function. 
 * Using some() to check if atleast 1 element from equipe is present in Set. 
 * If yes then checked.has(element) evaluates to true and some() receives atleast 1 element is valid and the element passes the filter.
 */

let filtered = planning.filter(plan => {
    return plan.equipe.some(element => checked.has(element));
})

console.log(filtered)

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