Looping array issue

Question

I'm having hard time trying to figure out how to loop through a simple array. I have this text file and basically my goal is selecting all lines starting with digits and an a (which in english is the equivalent to 1st, 2nd, 3th, 4th and so forth) and assign them with the proper score. So I have written this code:

#!/usr/bin/awk -f
BEGIN{FS="\t"}
/[0-9]+a/ {for (i=1; i<NR; i++) { score[i]=$3 } for (i=1; i<NR; i++) {print i, score[i]}}

and this is the crazy output I'm getting:

and I don't understand how it is possible. Can you please give me help?

By now I have figured out NR is not the total number of rows, but it updated each time a new row is processed. Now I need to know how to correcly store the scores into my array. — haunted85
– haunted85, Commented Jul 13, 2011 at 9:32

mbq · Accepted Answer · 2011-07-13 09:53:12Z

1

While awk arrays are rather hashes, there is no problem in feeding them with data; you just need:

/[0-9]+a/{scores[$1]=$2}

and scores['1a']=25, scores['3a']=16, etc.

You can loop though it using for-in loop:

/END/{for(e in scores) print(e,scores[e])}

answered Jul 13, 2011 at 9:53

mbq

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Comments

Zsolt Botykai · Accepted Answer · 2011-07-13 09:34:34Z

0

You don't need an array for that:

awk '/^[0-9]a/' YOURINPUT 
1a      25
2a      20
3a      16
4a      13
5a      11
6a      10
7a      9
8a      8
9a      7

answered Jul 13, 2011 at 9:34

Zsolt Botykai

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2 Comments

haunted85 Over a year ago

Yes, I do because I need it in order to perform another task.

Zsolt Botykai Over a year ago

In that case see the answer by @mbq

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