I have a numpy array which contains hours from 4 days:
s = np.array([0.0, 1.0, 2.0, 3.0, 4.0 ....96.0])
I want to create a datetime object from that.
I know that the first element is at timestamp 2021-03-21 00:00, so:
start_date = datetime.datetime.strptime('2021-03-21 00:00', '%Y-%m-%d %H:%M')
How can I create a new array which contains datetimes, incremented by an hour from the s array.
Use timedelta to build your new array:
>>> import numpy as np
>>> from datetime import datetime, timedelta
>>> s = np.array([0.0, 1.0, 2.0, 3.0, 4.0, 96.0])
>>> start_date = datetime.strptime('2021-03-21 00:00', '%Y-%m-%d %H:%M')
>>> [start_date + timedelta(hours=diff) for diff in s]
[datetime.datetime(2021, 3, 21, 0, 0), datetime.datetime(2021, 3, 21, 1, 0), datetime.datetime(2021, 3, 21, 2, 0), datetime.datetime(2021, 3, 21, 3, 0), datetime.datetime(2021, 3, 21, 4, 0), datetime.datetime(2021, 3, 25, 0, 0)]
unsupported type for timedelta hours component: numpy.float32. The same if I try to convert to integers
hours=int(diff)?int_ to convert to int and then use item to access the Python value, like that: [start_date + timedelta(hours=diff.item()) for diff in np.int_(s)]
start_date_incremented = [x + datetime.timedelta(hour = 1) for x in start_date_array]