I have got a function that has 2 arguments + 1 optional argument. I want to run that function in loop basing on lists with different length and don't know how to really do it. The function and loop would look like this:
def function(x,y,z=1):
print(x,y,z)
LIST = [(1,1,1), (2,3,4), (5,6), (7,8), (9,9,9)]
for i in LIST:
print(function(i[0], i[1], i[2]))
of course I could write smth like if len(i) = 2: (...) in loop but I wonder if I can do it a better way.
The easiest way is to use *args:
def function(x, y, z=1):
print(x, y, z)
LIST = [(1,1,1), (2,3,4), (5,6), (7,8), (9,9,9)]
for i in LIST:
function(*i)
*args though, the original prototype works just fine.
*i will match positional arguments onlyYou can expand the tuple and pass it as argument as Pawel has mention. *args will not be needed in this case.
def function(x,y,z=1):
print(x,y,z)
LIST = [(1,1,1), (2,3,4), (5,6), (7,8), (9,9,9)]
for i in LIST:
function(*i)
