C programming: How to printf an array of integers as a 2d array?

Question

I have an array of integers: int* list = malloc((m*n) * sizeof(int)); Variables m and n are the required dimensions of a 2d array.

I filled my array with random numbers and printed it with a simple for (int i = 0; i < lines; i++) printf("%d\n", list[i]); Which prints:

My question is how can I print the array as a 2d array instead of 1d?

Here's my attempt:

for (int i = 0; i < n; i++)
    {
        for (int j = 0; j < m; j++)
        {
            printf("%d", list[i]);
        }
        printf("\n");
    }

But this prints first n numbers like this:

444
555
100100100

Leaving the rest of the array lost somewhere.

list[i] -> list[i*m+j].

interjay
– interjay

2021-03-27 13:13:59 +00:00
Commented Mar 27, 2021 at 13:13 — interjay
– interjay, Commented Mar 27, 2021 at 13:13
@interjay yep that was the solution. Thanks :)

Nikola
– Nikola

2021-03-27 14:14:15 +00:00
Commented Mar 27, 2021 at 14:14 — Nikola
– Nikola, Commented Mar 27, 2021 at 14:14

MikeCAT · Accepted Answer · 2021-03-27 13:13:47Z

1

The first row (i = 0) should print the element 0, 1, ... , m-1.

The second row (i = 1) should print the element m, m+1, ..., 2*m-1.

The ith row should print the element m*i, m*i+1, ... , m*i+m-1.

Therefore, you should print list[i*m+j] instead of list[i].

Also you may want to add some space between the elements in the same row.

answered Mar 27, 2021 at 13:13

MikeCAT

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1 Comment

Nikola Over a year ago

I know about the spaces, I forgot to write that down. This fixed my problem. Thanks a lot :)

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