Is it possible somehow to preform logical functions on arrays like eg.
a= [1,2,3,4,5,6]
b= [1,3,5,7]
c= a and b
resulting in c=[1,3,5]
so only the values that are present in both the arrays.
The same with or eg:
d = a OR b
resulting in b=[1,2,3,4,5,6,7]
Is this possible somehow in python or are there short functions for this? Thanks for your response
Lists do not support logical operations , but you can do it in sets:
a= [1,2,3,4,5,6]
b= [1,3,5,7]
c = list(set(a) | set(b))
d = list(set(a) & set(b))
print(c)
# OUTPUT: [1, 2, 3, 4, 5, 6, 7]
print(d)
# OUTPUT: [1, 3, 5]
You probably should use python set if your collections contain unique values. They are actually mathematical sets: https://en.wikipedia.org/wiki/Set_(mathematics) and support general operation for sets such as intersection and union
>>> a = {1, 2, 3, 4, 5, 6}
>>> b = {1, 3, 5, 7}
>>> c = a.intersection(b)
>>> c
{1, 3, 5}
Here is your snippet:
def and_array(a, b):
return [a[i] for i in range(min(len(a), len(b))) if a[i] in b or b[i] in a]
def or_array(a, b):
return a + [element for element in b if not element in a]
a= [1,2,3,4,5,6]
b= [1,3,5,7]
c = and_array(a, b)
d = or_array(a, b)
print(c)
print(d)
Result:
[1, 2, 3]
[1, 2, 3, 4, 5, 6, 7]
It is not that fast, avoid this for very large lists and use numpy or build-in functions!
