How to store 'for i in range' loop output

Question

I wrote these lines to import zip file with log files in it:

from google.colab import drive
drive.mount('/content/drive')

from zipfile import ZipFile
df_ht =  !unzip "/content/drive/MyDrive/HTWebLog_p1.zip"

To read the log file:

file = open('ex061101.log', 'r')
print(file)

output:

<_io.TextIOWrapper name='ex061101.log' mode='r' encoding='UTF-8'>

lines = file.read().splitlines()
lines[5:6]

Output:

['2006-11-01 00:00:08 W3SVC1 127.0.0.1 GET /Tulip/home/en-us/home_index.aspx - 80 - 70.80.84.76 Mozilla/4.0+(compatible;+MSIE+6.0;+Windows+NT+5.1;+SV1) - 200 0 0']

Now I am trying to store the loop output, but I only get the last log file (judging by the length of it):

for i in range(212,229):
    lines = (open(str('ex061') + str(i) + str('.log'), 'r', encoding='iso-8859-1')).read().splitlines()
len(lines)

EDIT.

I found the solution:

import itertools

lines = [] 

for i in range(212,229): 
    lines = (open(str('ex061') + str(i) + str('.log'), 'r', encoding='iso-8859-1')).read().splitlines() 
output=list(itertools.chain(lines))

Yeah, you’re just overwriting the same variable again and again. You might want to make a list and append to it? — deceze
– deceze ♦, Commented Apr 5, 2021 at 5:01
And, by the way, 'ex061' and '.log' are already strings, You don't have to wrap them in str(). You might even consider f"ex061{i}.log". — Tim Roberts
– Tim Roberts, Commented Apr 5, 2021 at 5:07
Thank you, I did it by: 'lines = []' before loop and after loop this line: output=list(itertools.chain(lines)) — Nastya L
– Nastya L, Commented Apr 5, 2021 at 5:08

SomeGuy · Accepted Answer · 2021-04-05 05:09:44Z

1

In the for loop you write the variable lines but because it loops you over write it every time it loops which is why you are only getting the last values, a better way is to create a list and add to it every time you loop which will not over write it and store it nicely.

list = []

for i in range(212, 229):
   list.append(open(str('ex061') + str(i) + str('.log'), 'r', encoding='iso-8859-1')).read().splitlines())

I havent tested the code out but should work

answered Apr 5, 2021 at 5:09

SomeGuy

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2 Comments

Nastya L Over a year ago

There is an error: AttributeError: 'NoneType' object has no attribute 'read'. Your previous deleted response didn't work as well because of that error: AttributeErrorError: sequence item 0: expected str instance, list found. But I got some ideas from that join function and eventually got this: lines = [] for i in range(212,229): lines = (open(str('ex061') + str(i) + str('.log'), 'r', encoding='iso-8859-1')).read().splitlines() output=list(itertools.chain(lines)) It works.

SomeGuy Over a year ago

Good to know, I didnt test the code, i just wanted to show you the list and the append aspect of it all

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