Requirement is to find a string from txt file and store it to variable.
file look like this(rsa.txt)
Encrypting String
... Input string : Test_123
... Encrypted string : $ENC(JEVOQyhZbVpkQmM0L3ArT2c4M05TZks5TmxRPT1+KQ==)
Required output (variable name : encstring):
encstring = $ENC(JEVOQyhZbVpkQmM0L3ArT2c4M05TZks5TmxRPT1+KQ==)
I tried below code but showing no result
encstring=$(grep -oE '$ENC[^()]*==)' <<< rsa.txt)
With awk, could you please try following. Simply, search for string /Encrypted string along with a condition to check if last field of that line has $ENC in it then last field for that line by using $NF.
encstring=$(awk '/Encrypted string/ && $NF~/\$ENC/{print $NF}'
You can use
encstring=$(sed -n 's/.*\(\$ENC(.*)\).*/\1/p' rsa.txt)
# OR
encstring=$(grep -oP '\$ENC\(.*?\)' rsa.txt)
See an online demo:
s='Encrypting String
... Input string : Test_123
... Encrypted string : $ENC(JEVOQyhZbVpkQmM0L3ArT2c4M05TZks5TmxRPT1+KQ==)'
encstring=$(sed -n 's/.*\(\$ENC(.*)\).*/\1/p' <<< "$s")
echo "$encstring"
# => $ENC(JEVOQyhZbVpkQmM0L3ArT2c4M05TZks5TmxRPT1+KQ==)
The sed -n 's/.*\(\$ENC(.*)\).*/\1/p' command does the following:
-n suppresses the default line outputs/.*\(\$ENC(.*)\).*/\1/ - finds any text, then captures $ENC(...) into Group 1 and then matches the rest of the string, and replaces the match with the Group 1 valuep - prints the result of the substitution.The grep -oP '\$ENC\(.*?\)' command extracts all $ENC(...) matches, with any chars, as few as possible, between ( and ).
You are searching for ENC which is followed by 0 or more occurances of something which is not an open or closed parenthesis. However, in your input file, there is an open parenthese after ENC. Therefore [^()]* matches the null string. After this you expect the string ==). This would match only for the input ENC==)`.
You need to escape $ as \$ as it means "end of string" with -E
$ENCwhich is not followed by an open or closed parenthesis. However, in your input file, there is an open parenthese after$ENC.