Python ignore regex

Question

I am actually working on Python regex that excludes certain file path. I am creating this regex in a property file , and then passing to my python code

import re
regex = ".*-old-.*"
sequence = "/tmp/file-old-1"

print re.match(regex, sequence)

Now , I want to build a regex that do not match for anything. Is it possible to have so. Any help will be helpful !

Thanks !

What do you mean? typically regex is used to match strings containing a pattern you define. When you say do not match anything, do you mean perform an action if your current regex has no match? Whats your input and expected output? — PacketLoss
– PacketLoss, Commented Apr 7, 2021 at 1:39
You tagged this for python-3.x, and it has a syntax error for Python 3, and guaranteed broken code in any version of Python (// is not a comment character in Python, so you're trying to divide the result of re.match by True). If you're going to provide code samples, at least make them legal code. — ShadowRanger
– ShadowRanger, Commented Apr 7, 2021 at 1:44

jsbueno · Accepted Answer · 2021-04-07 01:43:22Z

1

There are the special characters ^ and $ to denote the beggining and ending of the text being matched. Any pattern that have text before the beggining or after the end will have no match:

In [113]: re.findall(r".^", "any text")
Out[113]: []

answered Apr 7, 2021 at 1:43

jsbueno

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