how to compare array element of one array with elements in another array in bash?

Question

I have stored some strings in array1, lets say

array1[0]=apple
array2[1]=orange

and array2 contains

array2[0]=apple
array2[1]=mango

I want to loop through each element and check if they match. I tried using this condition inside loop but it didnot work

if [ "$array[i]" = "$array2[j]" ]

I don't see a loop in your posting. Complementing the answer given by Socowi: If you prefer the array access syntax you are using, you could consider switching to zsh (which also would make the quotes unnecessary). Bear in mind that array indexing in zsh starts with 1. — user1934428
– user1934428, Commented Apr 7, 2021 at 10:12

Socowi · Accepted Answer · 2021-04-07 09:47:03Z

1

To access the elements of an array in bash you have to use ${array[i]} instead of just $array[i]. Because the [ cannot normally be part of a variable name, bash interprets $array[i] as ${array} followed by a literal [i].

By the way: https://www.shellcheck.net/ would have found this error.

answered Apr 7, 2021 at 9:47

Socowi

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totalNoob Over a year ago

thanks, the problem was in syntax, it solved my doubt.

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