How to split string with multiple delimiters in Python?

Question

My First String

xxx.xxx.com-bonding_err_bond0-if_eth2-d.rrd.csv

But I want to result like this below

bonding_err_bond0-if_eth2

I try some code but seems not work correctly

csv = "xxx.xxx.com-bonding_err_bond0-if_eth2-d.rrd.csv"

x = csv.rsplit('.', 4)[2]

print(x)

But Result that I get is com-bonding_err_bond0-if_eth2-d But my purpose is bonding_err_bond0-if_eth2

you could split the output again on - and join the required slice: x = '-'.join(x.split('-')[1:-1]) — Krishna Chaurasia
– Krishna Chaurasia, Commented Apr 9, 2021 at 4:27
Are you needing to search for similar strings which may have different interface id's? Will the pattern change? — PacketLoss
– PacketLoss, Commented Apr 9, 2021 at 4:29

Shashank Mistry · Accepted Answer · 2021-04-09 04:31:44Z

2

If you are allowed to use the solution apart from regex, You can break the solution into a smaller part to understand better and learn about join if you are not aware of it. It will come in handy.

solution= '-'.join(csv.split('.', 4)[2].split('-')[1:3])

Thanks, Shashank

answered Apr 9, 2021 at 4:31

Shashank Mistry

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Neeraj · Accepted Answer · 2021-04-09 04:40:57Z

1

Probably you got the answer, but if you want a generic method for any string data you can do this:

In this way you wont be restricted to one string and you can loop the data as well.

csv = "xxx.xxx.com-bonding_err_bond0-if_eth2-d.rrd.csv"

first_index = csv.find("-")
second_index = csv.find("-d")

result = csv[first_index+1:second_index]
print(result)
# OUTPUT:
# bonding_err_bond0-if_eth2

answered Apr 9, 2021 at 4:40

Neeraj

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user14185615 · Accepted Answer · 2021-04-09 04:33:48Z

1

You can just separate the string with -, remove the beginning and end, and then join them back into a string.

csv = "xxx.xxx.com-bonding_err_bond0-if_eth2-d.rrd.csv"

x = '-'.join(csv.split('-')[1:-1])

Output

>>> csv
>>> bonding_err_bond0-if_eth2

answered Apr 9, 2021 at 4:33

user14185615

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