I was trying bubble sort through define function method but it keeps on showing attribute error. I am not able to understand the reason, so if anyone could explain this error it would be a great help.
l=[1,4,7,9,0]
def kono():
n=len(l)
for i in range (n):
for j in range(n-i-1):
if(l[j]>l[j+1]):
l[j],l[j+1]=l[j+1],l[j]
b=l.kono()
print(b)
Change your code so that the function takes a list; then, to call it, use kono(l) instead of l.kono(); then there's no need to assign the result to b since the list is passed as a reference (also the function doesn't return any value):
l=[1,4,7,9,0]
def kono(l):
n=len(l)
for i in range (n):
for j in range(n-i-1):
if(l[j]>l[j+1]):
l[j],l[j+1]=l[j+1],l[j]
kono(l)
print(l)
return statement in your function, so assigning values to it will always result in None values. In Python lists (and objects in general) are passed as reference, so changing them inside the function will cause them to also change outside.
If you want you can add a return. All depends on how you want to define your function
l=[1,4,7,9,0]
def kono(l):
n=len(l)
for i in range (n):
for j in range(n-i-1):
if(l[j]>l[j+1]):
l[j],l[j+1]=l[j+1],l[j]
return l
b = kono(l)
print('This is b',b)
#Output: This is b [0, 1, 4, 7, 9]
In this case, you will assign the ordered list to b.
l.kono()to mean?def kono(l)and the call tokono(l).