Getting an "undefined index" error

Question

I'm making an activation page that is getting mailed to the user after they register to the website, but i'm having an error in my code:

Undefined index: ActivationKey

the link the user will get will be like

website-url/activate.php?Username=user&ActivationKey=foobar

it gives the error on this line of code:

$ActivationKey = $_SESSION['ActivationKey'];

my code is the following:

<?PHP



//Include database connection details
require_once('config.php');

//Array to store validation errors
$errmsg_arr = array();

//Validation error flag
$errflag = false;

//Connect to mysql server
$link = mysql_connect("127.0.0.1","root","XXX");
if(!$link) {
    die('Failed to connect to server: ' . mysql_error());
}

//Select database
$db = mysql_select_db("monitron");
if(!$db) {
    die("Unable to select database");
}


//Start session
session_start();    


//check if Username is already in session and
//use it if it is
//else, grab it from GET
//use it from GET
if(!empty($_SESSION['Username'])){
$Username = $_SESSION['Username'];
}else if(isset($_GET['Username'])){
$_SESSION['Username'] = $_GET['Username'];
$Username = $_SESSION['Username'];
};


//Grab activationkey from session.

if(isset($_GET['ActivationKey'])){
$_SESSION['ActivationKey'] = $_GET['ActivationKey'];
};

$ActivationKey = $_SESSION['ActivationKey'];

echo $ActivationKey;
echo $Username;

//Create update query to update activation status
$qry = "UPDATE login SET ActivationStatus = 'Active' WHERE Username = '$Username'";
$result = @mysql_query($qry)

?>

i'd appreciate it if somebody could help me out on this :)

i think that line should move inside the if statement just before it. — Gabriel Spiteri
– Gabriel Spiteri, Commented Jul 15, 2011 at 10:05
var_dump($GET,$_SESSION) gives me array 'Username' => string 'xvampx' (length=6) 'Activationkey' => string 'df5097bfcf58e61af7c48603a47c5288' (length=32) array 'Username' => string 'xvampx' (length=6) — Christoph
– Christoph, Commented Jul 15, 2011 at 10:12

Ólafur Waage · Accepted Answer · 2011-07-15 10:05:15Z

1

You have the lines

if(isset($_GET['ActivationKey'])){
    $_SESSION['ActivationKey'] = $_GET['ActivationKey'];
};

$ActivationKey = $_SESSION['ActivationKey'];

But what if the if statement never is true, then there is no $_SESSION['ActivationKey'] and that is the error PHP is complaining about.

answered Jul 15, 2011 at 10:05

Ólafur Waage

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3 Comments

Christoph Over a year ago

but it should be true, because in the link the activationkey is set. it should grab the string and put it into the $activationkey variable.

Jatin Dhoot Over a year ago

checkyour Username value ---- I guess it might be containing some space etc weird HTML char ---- what username you are supplying?

Christoph Over a year ago

see my comment on the answer above, when i use var dump $GET $SESSION it displays the activationkey in GET but not in SESSION. so it's getting the username right.

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