Jupyter import Python function

Question

I have the following folder structure

main/
     jupyter/
            nb.ipynb
     helper/
           text.txt
           foo/
              foo.py

The file foo.py contains

def foo():
    open("../text.txt", "r")

In the jupyter notebook I have

import sys
sys.path.append("../helper/foo")
from foo import foo

foo()

which gives a file not found error. What's the cleanest way of fixing that? (If possible, I'd like to keep foo.py unchanged.)

Martin Ueding · Accepted Answer · 2021-04-16 14:16:41Z

2

You get this error because the path is relative to your working directory. You will need to change it using os.chdir('../helper/foo').

It would be a bit better to change foo.py and use os.path.join(os.path.dirname(os.path.dirname(__file__)), 'text.txt') as path.

edited Apr 16, 2021 at 14:16

answered Apr 16, 2021 at 13:10

Martin Ueding

8,8076 gold badges53 silver badges99 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

julian Over a year ago

Thanks a lot for the answer. I also think that the second part is actually better. Only a small typo: it should be __file__.

Martin Ueding Over a year ago

In the grander scheme you could also think about making your helper code an actual package and then load the file with pkgresources. — And thanks for the __FILE__ hint, I was still in C++ mode in my mind.

Wuhuuu2 · Accepted Answer · 2021-04-16 13:19:49Z

0

It is sufficient to just go one level up and search there for your folder & module

import sys
sys.path.append("../")  # just one level higher
from folder.module import function

function()

answered Apr 16, 2021 at 13:19

Wuhuuu2

251 silver badge5 bronze badges

Collectives™ on Stack Overflow

Jupyter import Python function

2 Answers 2

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related