Using Python's distutils.core, compiler links in Python 2.7 instead of Python 3

Question

I've got a package with swig wrapping C for Python that I'm trying to upgrade to Python 3. I'm building it under Linux (CentOS) (provided in a Docker environment).

My problem is that the compile and link options assume I'm using Python 2.7. That is, the compile includes

-I/usr/include/python2.7

and the link includes

-lpython2.7

I got the compilation to work by including a compile option to find the Python 3 include directory:

CC="gcc -I/usr/include/python3.6m" python setup.py build_ext

but the link is failing due to not finding the python2.7 library:

/usr/bin/ld: cannot find -lpython2.7 collect2: error: ld returned 1 exit status

How do I tell distutils I'm a Python 3 shop now? "python" already gives "python3".

This is the command line to tell swig that you use python3. I will recommend that you simply use the distutils from Python3, e.g. in virtual environment. Check also the setup.py script if there is anything pointing to python 2.7 — Jens Munk
– Jens Munk, Commented Apr 28, 2021 at 12:24
Thanks, phd. I'll try to figure out how to get -py3 to the swig command (I don't give it explicitly; distutils figures it out from a source being ".i"). — Ethan Bradford
– Ethan Bradford, Commented Apr 28, 2021 at 14:59
Thank you, Jens. I thought I was running setup.py with Python 3, because I have an alias of "python" -> "python3", but that wasn't respected by the calling (Python 3) script. Explicitly asking for python3 in the calling script fixed everything. — Ethan Bradford
– Ethan Bradford, Commented Apr 28, 2021 at 15:08

Ethan Bradford · Accepted Answer · 2021-04-28 15:10:49Z

1

As Jens pointed out, though I thought I was calling setup.py with Python 3, I was actually using Python 2. Fixing that to Python 3 solved my problem.

answered Apr 28, 2021 at 15:10

Ethan Bradford

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