How to get value from JSON response from array of dictionary in swift

Question

unable to get Array of dictionary value

this is my model

public var featured_product : Array<Featured_product>?

    public class Featured_product {
    public var wishlist : wishlist?
    }

     required public init?(dictionary: NSDictionary) {
       if (dictionary["wishlist"] != nil) { wishlist = Aswagna.wishlist(dictionary: dictionary["wishlist"] as? NSDictionary ?? NSDictionary())}
   }

public class wishlist {
public var id : Int?
}

here i want wishlist-> id.. for that i have tried like below

@IBAction func addToWishList(_ sender: UIButton){
 
    if let data = self.homDB?.result?.product?.featured_product{

        for wishlistData in data.wishlist ?? []{

            idFav = wishlistData["id"]
        }
    }
    
}

error in for loop data.wishlist

Value of type '[Featured_product]' has no member 'wishlist'

how do i get wishlist id.. please do help

Edit: addToWishList is the collectionview cell button action.. i have given its action to HomeVC from storyboard cell

class HomeVC: UIViewController{
var homDB = HomeDataModel(dictionary: NSDictionary())
@IBAction func addToWishList(_ sender: UIButton){
 //here i need selected button's wishlist id
  
  idFav = self.homDB?.result?.product?.featured_product?[sender.tag].wishlist?.id
  print("wishlist id \(idFav)")
 }

}

if i do like above then print("wishlist id \(idFav)") getting nil.. where am i wrong.. pls do help.

Olivier · Accepted Answer · 2021-04-29 12:57:13Z

1

The first error is straightforward. The error message states thatdata is an array of Featured_product and that the array has no member wishlist. You need to access the individual array element before accessing wishlist:

    for wishlistData in data ?? []{

        idFav = wishlistData["wishlist"].id
    }

Regarding the second one, I would suggest to unwrap each element of your chain one at time to get a better understanding of which one is nil.

edited Apr 29, 2021 at 12:57

answered Apr 29, 2021 at 12:49

Olivier

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