I have a block of code in $(function() { function parseData(){...} )};
I also have a function declared outside of the ready block. This is outside since I hook it up in codebehind ie ddlCategories.Attributes.Add("onchange", "getDataFields()");
From the getDataFields function, I need to call parseData but it does not seem to find it.
How do I access my parseData() which is in my ready block, from outside of the ready block?
(sorry if some of terminology is off - I am now to JS)
Any reason parseData() has to be in the ready block? Why not just make it a top level function:
<script type="text/javascript">
function parseData() { ... }
$(document).ready( function() {
ddl.Categories.....
}
<script>
Just define it outside your ready block. It's currently inaccessible due to the scope of the function.
Definitions can always safely go outside $(function() { ... }) blocks because nothing is executed.
$(function() { ... });
function parseData() { ... }
However, you seem to have a syntax error: )}; should be });.
$(...) blocks. Otherwise, those functions would not be accessible outside the $(...). This behaviour is called 'scope'.Declare your parseData function outside of the self-executing $(function(){}); block.
var parseData = function () { ... };
$(function() { ... });
If there are things you need to reference inside the self-executing function, then declare the function globally but define it inside the self-executing function:
var parseData;
$(function() { parseData = function () { ... }; });
As an aside, declaring functions or variables globally is a bad idea.
