Is there a way to extract the url of images my my css file in python? [duplicate]

Question

I am trying to get all the urls of images that are used within a css file. For example this is part of my css file:

sitewrap {
    width: 890px;
    margin: 0 auto;
    background: #ffffff url(../images/bg_sitewrap.gif) repeat-y;
}

How can receive just the ../images/bg_sitewrap.gif section of it, in python preferably?

Thanks in advance for the assistance!

Tim Biegeleisen · Accepted Answer · 2021-05-07 06:14:59Z

2

You could try using re.findall here:

css = """sitewrap {
    width: 890px;
    margin: 0 auto;
    background: #ffffff url(../images/bg_sitewrap.gif) repeat-y;
}"""

urls = re.findall(r'\burl\((.*?)\)', css)
print(urls)  # ['../images/bg_sitewrap.gif']

This answer assumes that you would want to capture every instance of url(...) in your CSS script. If not, then you might need to use a CSS parser/library, before perhaps using regex later in the pipeline to find the URLs.

answered May 7, 2021 at 6:14

Tim Biegeleisen

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